-8x-2/3x^2+6x+3=-1/2

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Solution for -8x-2/3x^2+6x+3=-1/2 equation: 


x in (-oo:+oo)

6*x-((2/3)*x^2)-8*x+3 = -1/2 // + -1/2

6*x-((2/3)*x^2)-8*x-(-1/2)+3 = 0

(-2/3)*x^2-8*x+6*x+1/2+3 = 0

7/2-2/3*x^2-2*x = 0

DELTA = (-2)^2-(-2/3*7/2*4)

DELTA = 40/3

DELTA > 0

x = ((40/3)^(1/2)+2)/(-2/3*2) or x = (2-(40/3)^(1/2))/(-2/3*2)

x = -3/4*((40/3)^(1/2)+2) or x = -3/4*(2-(40/3)^(1/2))

x in { -3/4*((40/3)^(1/2)+2), -3/4*(2-(40/3)^(1/2)) }

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